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JEE (Joint Entrance Examination) Advanced 2020 is a national level entrance test which provides admission to the UG programmes offered at the IIT’s and other institutes which accepts the JEE Advanced score. Each year, out of the 23 IIT’s one of the IIT remains as the conducting body. For the year 2020, the conducting body […] The post JEE Advanced 2020 – (Joint Entrance Exam Advanced 2020) appeared first on...
JEE (Joint Entrance Examination) Advanced 2020 is a national level entrance test which provides admission to the UG programmes offered at the IIT’s and other institutes which accepts the JEE Advanced score. Each year, out of the 23 IIT’s one of the IIT remains as the conducting body. For the year 2020, the conducting body of JEE mains and JEE advanced is IIT Delhi . Aspirants to apply for JEE Advanced only after clearing JEE Mains. The official notification for JEE Advanced 2020 is expected to be released in the 1st week of May,2020. Test will be held on 17 May 2020 ( Sunday ).
For mock test , go on link here under:
Some important dates for JEE Advanced 2020 are given below:
|Events||Important Dates (Tentative)|
|Registrations begins||1st week of May 2020|
|Registrations closes||2nd week of May 2020|
|Download Exam Admit card||3rd week of May 2020|
|JEE Advanced 2020 Exam date|| 17 May 2019 ( Sunday)|
Paper 1 : 09:00 – 12:00 IST
Paper 2 : 14:30 – 17:30 IST
|Answer Key Release||Last week of May 2020|
|Result Declaration||08 JUN 2020|
|Seat allotment begins||17 Jun 2020|
|Seat allotment ends||3rd week of July 2020|
JEE Advanced 2020 will be held in the 17May 2020 ( Sunday)
Paper 1 : 09:00 – 12:00 IST
Paper 2 : 14:30 – 17:30 IST
JEE Advanced will be conducted in online mode (computer based test), in objective format.
JEE Advanced paper is bilingual. i.e., English and Hindi. The candidates can choose the language in which they wish to take the exam.
|Indian Institute of Technology – Bombay||Mumbai|
|Indian Institute of Technology – Delhi||New Delhi|
|Indian Institute of Technology – Kharagpur||Kharagpur|
|Indian Institute of Technology – Roorkee||Roorkee|
|Indian Institute of Technology – Madras||Chennai|
|Indian Institute of Technology – Guwahati||Guwahati|
|Indian Institute of Technology – Kanpur||Kanpur|
|Indian Institute of Technology – Gandhinagar||Gandhinagar|
|Indian Institute of Technology – Ropar||Roopnagar (Punjab)|
|Indian Institute of Technology – Hyderabad||Hyderabad|
|Indian Institute of Technology – Mandi||Mandi (Himachal)|
|Indian Institute of Technology – Patna||Patna|
|Indian Institute of Technology – Palakkad||Palakkad (Kerla)|
|Indian Institute of Technology – Jodhpur||Jodhpur (Rajasthan)|
|Indian Institute of Technology – Indore||Indore|
|Indian Institute of Technology – Banaras (BHU)||Varanasi (UP)|
|Indian Institute of Technology – Bhubneswar||Bhubneswar|
|Indian Institute of Technology – Tirupati||Tirupati (A.P)|
|Indian Institute of Technology – Bhilai||Bhilai|
|Indian Institute of Technology (ISM Dhanbad) – Dhanbad||Dhanbad (Jharkhand)|
|Indian Institute of Technology – Jammu||Jammu|
|Indian Institute of Technology – Dharwad||Dharwad|
|Indian Institute of Technology – Goa||Goa|
|Indian Institute of Science Education & Research(IISER) – Bhopal||Bhopal|
|Indian Institute of Science Education & Research(IISER) – Mohali||Mohali (Punjab)|
|Indian Institute of Science Education & Research(IISER) – Kolkata||Kolkata|
|Indian Institute of Science Education & Research(IISER) – Pune||Pune|
|Indian Institute of Science Education & Research(IISER) – Tiruvanathapuram||Tiruvanathapuram (Kerala)|
|Indian Institute of Space Science & Technology (IIST) – Tiruvanathapuram||Tiruvanathapuram (Kerala)|
|Rajiv Gandhi Institute of Petroleum Technology (RGIPT) – Rae Bareli||Rae Bareli (U.P)|
|Indian Institute of Science (IISc) – Bangalore||Bangalore|
|Indian Institute of Petroleum & Energy(IIPE)-Visakhapatnam||Vishakapatnam|
The applying candidate must be an Indian citizen (including OCI/PIO) and foreign national candidates
A JEE aspirant must have cleared their 10+2 or equivalent examination in 2019 or 2020.
The candidate must have cleared JEE Main exam in order to apply for JEE Advanced.
Candidates must have scored 75% marks (65% for SC/ ST/ PWD category in 12th or equivalent examination.
Candidates will have to come under the top 2,24,000 qualifying candidates in paper 1 of JEE Main 2020 (including all categories). Higher score out of both JEE Jan 2020 and April 2020 will be considered.
Candidates will be able to apply for JEE Advanced for a maximum of two times in two consecutive years.
Candidates should have been born on or after 1st October, 1995. Reserved category i.e. SC/ST/PWD candidates get a 5year relaxation in age limit and hence those born on or after 1st October, 1990 are eligible to apply for this exam.
Currently the JEE Advanced 2020 application portal is closed.
Candidates can fill the JEE Advanced 2020 application form via online mode only.
Online registration for JEE Advanced 2020 will commence from 1st week of May 2020 and will go on till 2nd week of May 2020.
The Category wise application Fee for JEE Advanced 2020 is as follows: Based on JEE ( Advanced ) 2019 Notification
|General / Male candidates||Rs. 2600|
|SC/ST/OBC/PWD/Female Candidates||Rs. 1300|
|SAARC Countries||USD 75|
|Non-SAARC Countries||USD 150|
|Late Fee||USD 80|
JEE Advanced candidates are required to pay the application fee through Credit Card, Debit Card or Net Banking.
Candidates will have to fill their exam city preference ,personal and educational details along with the following details.
Latest photograph, signature along with thumb impression.
Students with certain specifications/quota must upload the required documents at the time of registration.
NOTE: If name on the 10thcertificate is not same as 12th certificate then, gazette notification showing the change of name must be uploaded.
No correction facility in the application form will be provided by the board so candidates must fill the details carefully.
The complete online application procedure for JEE Advanced is divided into 4 stages.
Regarding the JEE Advanced 2020 Admit Card, note the following Points:
The JEE Advanced 2020 Admit Card will be available from 3rd week of May 2020
The admit card will be made available on the official website through online mode only.
Candidates are required to download and take a print of their admit card as it will not be send via post.
The admit card which the candidate shall download will be a temporary admit card. At the test centre, the candidate shall be provided with the original admit card of JEE Advanced 2020. It is advised to the students that they keep the original admit card with them till the admission process gets over.
In case of any queries, contact the JEE Advanced 2020 help desk
The JEE Advanced 2020 exam pattern is as follows:
JEE Advanced 2020 will be conducted in online mode.
For JEE Advanced 2020 the candidates get 3 hours to answer the questions.
The candidates will have to attend JEE advanced 2020 paper 1 & 2
There will be Multiple Choice Questions (MCQ) /Numerical Ability Type.
|Exam Pattern||Section 1||Section 2||Section 3|
|Question Type||One or more options||Single Digit Integer(0-9)||Single Correct option|
|Number of Questions||7||5||6|
|Full Marks||+4 (If correct answers are marked)||+3 (for giving correct answer)||+3 (for giving correct answer)|
|Partial Marks||+1 ( for marking an answer corresponding to each correct option but no incorrect answer is marked)||–||–|
|Zero Marks||0( if no answer is marked)||0 ( in all other cases)||0 (if no answer is marked)|
|Negative Marks||-2 (in all other cases)||–||-1 (in all other cases)|
|Maximum Marks in the Examination||28||15||18|
|Exam Pattern||Section 1||Section 2||Section 3|
|Question Type||One or more options||Single Digit Integer(0-9)||Single Correct option|
|Number of Questions||7||7||4|
|Full Marks||+3 (for giving the correct answer)||+4 ( if correct answer is marked )||+3 ( if correct answer is marked)|
|Partial Marks||–||+1( for marking an answere corresponding to each correct option)||–|
|Zero Marks||0( if no answer is marked)||0( if no answer is marked)||0( in all other cases)|
|Negative Marks||-1 (in all other cases)||-2 ( in all other cases)||–|
|Maximum Marks in the Examination||21||28||12|
Regarding the result Declaration, the following points may be noted:
JEE advanced 2020 results will be announced probably in the 2nd week of June 2020
Candidates must check the results online on the official website by entering the Application number and Password and must keep a hard copy of the score card.
JEE Advanced results will be available for candidates who appeared for both the papers.
The JEE Advanced 2020 counselling process will be conducted from 3rd week of June 2020-3rd week of July 2020
The counselling will be in offline mode and It will be conducted by JoSAA or Joint Seat Allocation Authority.
A separate brochure will be released for the complete information for the choice filling and the counselling.
Candidates are requested to submit the required documents at the time of admission as per the instructions provided.
Answer: Yes, you are eligible to appear for JEE Advanced 2019, provided you comply with the set eligibility norms for the exam.
Answer: If you’re targeting IITs or ISM then you need to look out for JEE advanced score. Admission to NITs and IIITs is based solely on your JEE Mains score.
Answer:In JEE Advanced, you need to score at least 40% of the maximum marks (~240 out of 400).
Following are some important links for JEE Advanced 2020 Examination:
|Application of Links||Links|
|JEE Advanced 2020 Official Website||https://jeeadv.ac.in/|
|Admission portal||Yet to be uploaded|
|Online Application portal||Yet to be uploaded|
|JEE Advanced 2020 FAQ’s||https://jeeadv.ac.in/examination/faqs.html|
The post JEE Advanced 2020 – (Joint Entrance Exam Advanced 2020) appeared first on EduPadhai.
INTRODUCTION JEE Main 2020 is a national-level premier engineering entrance exam conducted by National Testing Agency (NTA). Implemented in 2013, the exam is the stage one of the 2-stage Joint Entrance exam system for admission to IITs. JEE Main scores fulfill the basic eligibility for candidates willing to study B.Tech programs at NITs, IIITs, CFTIs […] The post JEE MAIN-2020 ( January)|ADMIT CARD|IMPORTANT ADVISORY BY NTA appeared first on...
JEE Main 2020 is a national-level premier engineering entrance exam conducted by National Testing Agency (NTA). Implemented in 2013, the exam is the stage one of the 2-stage Joint Entrance exam system for admission to IITs. JEE Main scores fulfill the basic eligibility for candidates willing to study B.Tech programs at NITs, IIITs, CFTIs and other centrally funded Technical Institutions across the country. Apart from the central institutions, JEE Main scores also serve as the eligibility criteria for JEE Advanced 2020, to be conducted for admissions in IITs. The exam is conducted twice for next academic year 2020-21. The first exam will be conducted in month of January 2020 and wii be conducted from 06- 09 January 2020 at 233 cities throughout the country and abroad. The Admit Cards of candidates (who have paid the fees) have been uploaded and can directly be down loaded on following link:
Candidates must see Advisory given by NTA before appearing in Exam
Downloading of Admit Card Through Application Number and Password
Down loading of Admit card Through Application Number and date of birth:
NTA has Issued advisory for candidates who are appearing in JEE ( Mains). Candidates must go through it. Go on following link:
The post JEE MAIN-2020 ( January)|ADMIT CARD|IMPORTANT ADVISORY BY NTA appeared first on EduPadhai.
JEE Main is a top coveted engineering entrance exam of the country conducted by National Testing Agency (NTA), twice a year. Merit obtained in test form basis of admission in various B.E, B.Tech, B.Arch and B.Plan courses to the aspiring candidates. A large number of Engineering colleges including CFTIs ( Centrally Funded Technical Institutions) and NITs ( […] The post Normalization Procedure for Preperation Merit of JEE ( Main ) 2020 appeared first on...
JEE Main is a top coveted engineering entrance exam of the country conducted by National Testing Agency (NTA), twice a year. Merit obtained in test form basis of admission in various B.E, B.Tech, B.Arch and B.Plan courses to the aspiring candidates. A large number of Engineering colleges including CFTIs ( Centrally Funded Technical Institutions) and NITs ( National Institutions of Technology) accept JEE main score cards for admissions to eligible candidates. It is also stage one exam for two stage exam for admission in IITs. This is a qualifying exam to appear in JEE ( Advance). For next Academic year 2020-21, 1st exam will be conducted in month of January 2020 and 2nd will be in month of April 2020.
For JEE ( Main) 2020 Go on link :
The examination conducting body i.e. NTA conducts the test on multiple dates and that too, generally in two sessions per day. The candidates are given different sets of question papers per session and it is every likely hood that in spite of all efforts of maintaining equivalence among various question papers, the difficulty level of these question papers conducted in different sessions may not be exactly same. It is likely that some of the candidates are attempting relatively tougher set of questions when compared to other sets. The candidates who attempt the comparatively tougher examination are likely to get relatively lower marks as compared to those candidates who attempt the easier questions.. In such situation, to ensure that candidates are neither benefitted nor disadvantaged,“Normalization procedure based on Percentile Score” is used due to different difficulty level of the examination. With the objective of ensuring that a candidate’s true merit is identified, and that a level playing field is created in the above context, the Normalization Procedure, set out by the examination conducting body NTA for compiling the scores for multi session papers.
1 The Normalization procedure is an established practice for comparing candidate’s scores across the multi session papers and is similar to those which is being adopted in other educational selection tests conducted in India.
2 For normalization across sections, the percentile equivalence is used.
3 Percentile Scores: Percentile scores are scores based on the relative performance of all those who appear for the examination. Basically, the marks obtained are transformed into a scale ranging from 100 to 0 for each session of examinees.
4 The Percentile score is the Normalized Score for the examination for preparation of the merit lists instead of raw marks obtained by the candidate.
5 The Percentile Scores is calculated up to 7 decimal places to avoid bunching effect and reduce chances of tie.
6 The best of the two score of JEE ( Main) of the candidates appeared in both the attempts will be considered for preparation of final merit.
The overall merit / ranking shall be based on the Percentile scores of the total raw scores. In case two or more candidates obtain equal Percentile Scores in the Test, the inter-se merit of such candidates shall be determined in order of preference as follows:
(a) Candidates obtaining higher Percentile Score in Mathematics in the Test.
(b) Candidates obtaining higher Percentile Score in Physics in the Test.
(c) Candidates obtaining higher Percentile Score in Chemistry in the Test.
(d) Candidates older in age to be preferred.
NTA has published a detailed procedure ( with elaborated example) for calculating the percentile for final merit. Candidates can refer the same on link : Normalization Procedure
The post Normalization Procedure for Preperation Merit of JEE ( Main ) 2020 appeared first on EduPadhai.
Latest: Notification of SSC CHSL 2019 is likely to come on 03 December 2019. SSC CHSL 2019 is conducted for the recruitment of various posts such as: Lower Divisional Clerk (LDC) Court clerks Junior Secretariat Assistant (JSA) Postal Assistant (PA) Sorting Assistant (SA) Data Entry Operator (DEO). The Staff Selection Commission (SSC) by the government […] The post Staff Selection Commission Combined Higher Secondary Level test – SSC CHSL 2019 appeared first on...
Notification of SSC CHSL 2019 is likely to come on 03 December 2019.
SSC CHSL 2019 is conducted for the recruitment of various posts such as:
The Staff Selection Commission (SSC) by the government of India conducts, CHSL- Combined Higher Secondary Level test annually. This exam will be conducted in 3-tiers for recruiting Clerical staff for different departments of the government. The official SSC CHSL 2019notification is expected to be released in December,2019.
Some important dates for SSC CHSL 2019 are given below:
|Important Events||Tentative Dates|
|Registration begins||03 December 2019|
|Registration ends||10 January 2020|
|Last date for online application fee||To be notified later on|
|Last date for application fee via challan||To be notified later on|
|Release of admit card-Tier 1 exam||To be notified later on|
|SSC CHSL 2020 exam date Tier 1|| 16- 27 March 2020 |
( CBE Mode)
|SSC CHSL Result 2020 Tier 1||Yet to be notified|
|Release of admit card – Tier 2 exam||To be notified later on|
|SSC CHSL 2020 exam date Tier 2||28 Jun 2020 (Descriptive)|
|SSC CHSL Tier 2 Result 2020||Yet to be notified|
|Date for skill test||Yet to be notified|
The examwill be held on the following dates:
SSC CHSL 2019 Tier 1 exam date: 16- 27 March 2019( CBE Mode)
SSC CHSL 2019 Tier 2 exam date: 28 Jun 2019 (Descriptive)
SSC CHSL 2019Tier 1 will be conducted in online mode (computer-based test)
SSC CHSL 201920 Tier 2 will be conducted in offline mode in descriptive format.
SSC CHSL 2019 Tier 3 will be a skill-based & typing test
The examination will be conducted in English & Hindi. The candidate has the liberty to choose the medium of language in which they wish to appear for SSC CHSL.
SSC CHSL applicant must be under any one of the below stated category:
|Ex-service men||5 years|
|Physically Handicapped (PH) PH – General||37 years|
|PH – SC/ST||42 years|
|PH – OBC||40 years|
|Ex-Servicemen- General||30 years|
|Ex-Servicemen- SC/ST||35 years|
|Ex-Servicemen- OBC||33 years|
|Category||Payment in INR|
|Female/SC/ST/Ex-Servicemen /PH candidates||No fee|
The candidate can choose to pay the SSC CHSL 2019application fees in any one of the following methods:
|Scanned coloured photograph||4kb-12Kb||100 X 120 pixels||JPG/JPEG|
|Scanned Signature||1kb-12Kb||140 X 60 pixels||JPG/JPEG|
The complete online application procedure for SSC CHSL 2019 is divided into 5 stages.
The SSC CHSL 2019 Tier 1 Admit Card will be available from Last week of July 2019
The SSC CHSL 2019 Tier 2 Admit Card will be available from last week of September 2019
The admit card will be made available on the official website through online mode only in PDF format.
Candidates are required to download and take a print of their admit card as it will not be sent via post.
In case of any queries, contact the SSC CHSL help desk: https://sscportal.in/ssc-helpline
The SSC CHSL exam pattern is as follows:
|Particulars||TIER 1||TIER 2||TIER 3|
|Type of questions||Objective||Descriptive||Typing|
|Total no. of questions||100||2||NA|
|Sections||General Intelligence – 25Qs. Quantitative Aptitude – 25Qs. English Quantitative – 25Qs. GK – 25Qs.||Article Writing.Letter Writing.||Skill TestingTyping Test.|
|Duration||75 mins (100 Mins for VH/OH)||60 mins (80 mins for VH/OH)||10 mins (Typing Test).15 mins (Skill Test)|
|Negative marking||0.5 marks||NA||NA|
Marking: 2 marks per question
Negative marking: For each wrong answer, 0.5 marks will be deducted.
Duration: 75 minutes
|Subjects||No of Questions||Marks|
Marking: 100 marks in total
Minimum cut-off: Minimum of 33% in this section is required
Duration: 60 minutes
|Subjects||No of Questions||Marks|
Candidates qualifying Tier 1 and Tier 2 will only be allowed to take tier 3.
As per the type of post applied, the tests will be conducted as follows.
Typing Test for PA/ SA/ LDC and Court Clerks
|Medium of examination||Hindi or English as chosen by the candidate|
|Typing Speed for English||35 words/minute|
|Typing Speed for Hindi||30 words/minute|
|Total duration||10 minutes (30 minutes for VH)|
Skill Test for DEO
|Typing Speed of Data Entry||8000 key-depression/hour to qualify|
|Medium of examination||English|
|Total Printed matter provided||2000-2200 strokes/key-depression|
|Total Duration||15 minutes|
SSC CHSL 2019 Result date for Tier 1 & Tier 2 is yet to be announced.
After the results for Tier 1 &Tier 2 have been released, the qualifying candidates will be eligible to attend Tier 3 examination.
The final result of the exam will be declared only after the commencement of the Tier 3 examination.
|Post||Initial Vacancy||Vacancy as on 27th March 2018||Vacancy as on 12th June 2018||Vacancy as on 10th May 2019|
Answer: As on 2018, the basic pay scale was as follows:
|Post||Grade Pay (in Rs.)|
|Data Entry Operator||1900|
|Lower Division Clerk||1900|
Answer: SSC CHSL consists of two phases namely Written Test and Skill Test. There are no interviews in this examination.
Answer: SSC CHSL happens only once a year. It takes approximately a year for the completion of the whole process i.e. Tier 1 and then Tier 2 in SSC CHSL.
Following are some important links for SSC CHSL 2019 Examination:
|Application of Links||Links|
|SSC CHSL Official Website||https://ssc.nic.in/|
|SSC CHSL Mock test||http://thepracticetest.in/SSC/logincandidate.php|
|SSC CHSL help desk||https://sscportal.in/ssc-helpline|
|SSC CHSL 2020 Application portal||Yet to be uploaded|
for future updates.
The post Staff Selection Commission Combined Higher Secondary Level test – SSC CHSL 2019 appeared first on EduPadhai.
XLRI will release XAT 2020 admit card from 20 December 2019 onwards.Examination details and candidate’s information will be present in the XAT admit card. It is a mandatory document to be carried to the examination hall. Only successfully registered candidates can be able to download their admit card from 20 December 2020 onward. candidates qualifying […] The post XAT Admit card 2020 appeared first on...
XLRI will release XAT 2020 admit card from 20 December 2019 onwards.Examination details and candidate’s information will be present in the XAT admit card. It is a mandatory document to be carried to the examination hall. Only successfully registered candidates can be able to download their admit card from 20 December 2020 onward. candidates qualifying XAT 2020 exam will be granted admissions to B-Schools and XLRI’s member institutes.
For registration log on: XAT -2020 Registration
|Availability of admit card||20 December 2019 onward|
|Last date to download admit card||1st week of January (tentative)|
1.Registered candidates must login to the http://www.xatonline.in and click the Tab Log in with XAT ID and password
2.Click on “Download Admit card”
3.Check all the details carefully and if there is any correction,candidates will have to contact officials from XLRI Jamshedpur
4.Take a print out of the admit card for future reference and the same has to be carried to the examination hall.
1.Name of the candidate
3.Candidate’s Date of Birth
4.Date of test
10.Photograph and signature of the candidate
1.Candidates will not be allowed to the examination hall without their admit card
2.Along with admit card,candidates have to produce original identification proof (Aadhar card/Voter ID/Driving license/PAN card/Passport etc.,)
3.Candidates have to put their signature in the space provided in the admit card
4.Candidates have to paste a recent passport size photograph in the space provided in the admit card
Q.Whom should I contact if I am unable to download admit card?
Ans. You can contact officials through email firstname.lastname@example.org or toll free number 1800 419 2929
Q.Can I carry the photocopy of my original ID along with admit card?
Ans. Original ID has to be carried to the examination centre.
For official brochure go on link : http://XATBulletin2020.pdf
Last updated on October 6th, 2019 at 09:07 pm Introduction The Union Public Service Commission (UPSC) conducts the recruitment exam for Central Armed Police Forces (UPSC CAPF 2020) aspirants every year. This exam is for candidates who wish to join the Central Reserve Police Force (CRPF), Border Security Force (BSF), Indo-Tibetan Border Police (ITBP), Central […] The post UPSC Central Armed Police Forces – 2020 (UPSC CAPF – 2020) appeared first on...
Last updated on October 6th, 2019 at 09:07 pm
The Union Public Service Commission (UPSC) conducts the recruitment exam for Central Armed Police Forces (UPSC CAPF 2020) aspirants every year. This exam is for candidates who wish to join the Central Reserve Police Force (CRPF), Border Security Force (BSF), Indo-Tibetan Border Police (ITBP), Central Industrial Security Force (CISF) and Sashstra Seema Bal (SSB) as Assistant Commandant can apply for this exam. The recruitment process consists of 3 phases – Written test, Physical Standard Tests and Interview.
The official notification for UPSC CAPF 2020 will release on 22 April 2020.
|UPSC CAPF Notification||22nd April 2020|
|Registration||22nd April 2020|
|Last date to Apply||5th May 2020|
|Exam Date||9th August 2020|
UPSC CAPF 2020 shall be held on 9th August 2020.
The mode of answering for UPSC CAPF 2020 shall be Pen/Paper based.
UPSC CAPF 2020 exam will be conducted in both Hindi and English languages.
Qualified candidates will be recruited by following Central Armed Polices Forces as Assistant Commandant:
The UPSC CAPF selection procedure is divided into 3 stages
Note: Female candidates are excluded from the posts in ITBP.
Certain age relaxation are as follows:
|Ex-Servicemen/Civilian central govt. employees||Up to 5 years|
|Candidate domiciled in the state of J&K during 1st Jan 1980 to 31st Dec 1989||Up to 5 years|
UPSC CAPF 2020 application portal will open on 22nd April 2020.
Candidates can apply for the exam through the official website.
UPSC CAPF 2020 application fees is ₹200 only. Female and SC/ST candidates are exempted from the fees.
Candidates can pay the fees through following modes:
Candidates need to upload the following documents while registration:
The UPSC CAPF application forms will release in April 2020. Candidates can register themselves by following these simple steps:
UPSC CAPF 2020 Admit Card shall be released in the third week of July 2020.
Candidates can download the hall ticket from the official website by logging in.
The Exam Pattern is divided into 3 stages:
Written Test shall consist of 2 papers: Paper 1 and Paper 2.
|Paper I||General Ability & Intelligence||250|
|Paper II||General Studies Essay &Comprehension||200|
Paper 1 will be 2 hours long Objective test. It will be of a total of 250 marks.
A total of 125 questions will be asked each carrying 2 marks each. Negative marking of 1/3rd marks will be made for wrong answers.
|Type of Questions||MCQ based|
|Total number of questions||125|
|Total number of marks||250|
|Language||Hindi and English|
Paper 1 will have questions based on the following topics:
Paper 2 will be a 3-hours long test. The total marks shall be 200 marks. There will be 7 questions in total of descriptive manner.
|Type of Questions||Descriptive Type Questions|
|Total number of questions||7|
The syllabus for the test will be:
Candidates can locate their nearest UPSC exam centre from the list:
UPSC CAPF 2020 results will be declared in September 2020.
Candidates can check their results in the UPSC official website.
Selected candidates will be required to go for a physical endurance test and a medical.
|Categories||Paper 1||Paper 2||Final|
|Categories||Paper 1||Paper 2||Final|
Answer. Candidates belonging to general category, the final cut off according to last year would be around 190 marks. For OBC, 188 marks and for SC/ST, around 160 marks.
Answer. UPSC CAPF forms are released along the official notification. For 2020, it is expected that registration will begin by 22nd April 2020.
Answer. Yes, provided the student is 20 years old as of 1st August 2020, then they are eligible to apply.
|Application Portal||Yet to be released|
|Admit Card||Yet to be released|
|Results||Yet to be released|
The post UPSC Central Armed Police Forces – 2020 (UPSC CAPF – 2020) appeared first on EduPadhai.
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